Tính. 11/12 - 1/3 + 1/4

a) $\frac{11}{12}$ - $\frac{1}{3}$ + $\frac{1}{4}$

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b) 1 –$\left(\frac{1}{6}+\frac{1}{3}\right)$

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a) $\frac{11}{12}$ – $\frac{1}{3}$ + $\frac{1}{4}$ = $\frac{11}{12}$ – $\frac{4}{12}$ + $\frac{3}{12}$ = $\frac{10}{12}$ = $\frac{5}{6}$

b) 1 – $\left(\frac{1}{6}+\frac{1}{3}\right)$= $\frac{6}{6}$– $\left(\frac{1}{6}+\frac{2}{6}\right)$= $\frac{6}{6}$ – $\frac{3}{6}$ = $\frac{3}{6}$ = $\frac{1}{2}$